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8m^2/3mm=3
We move all terms to the left:
8m^2/3mm-(3)=0
Domain of the equation: 3mm!=0We multiply all the terms by the denominator
m!=0/1
m!=0
m∈R
8m^2-3*3mm=0
Wy multiply elements
8m^2-9m=0
a = 8; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·8·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*8}=\frac{0}{16} =0 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*8}=\frac{18}{16} =1+1/8 $
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